#### Answer

$f^{-1}(x) = \frac{1}{x} - 2$

#### Work Step by Step

$f(x) = \frac{1}{x + 2}$
$y = \frac{1}{x + 2}$
$x + 2 = \frac{1}{y}$
$x = \frac{1}{y} - 2$
$f^{-1}(x) = \frac{1}{x} - 2$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$f^{-1}(x) = \frac{1}{x} - 2$

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