College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises: 60

Answer

$f^{-1}(x) = \frac{3 + x }{8x + 4}$

Work Step by Step

$f(x) = \frac{3 - 4x}{8x -1}$ $y= \frac{3 - 4x}{8x -1}$ y(8x - 1) = 3 - 4x 8xy - y = 3 - 4x 8xy + 4x = 3 + y x(8y + 4) = 3 + y $x = \frac{3 + y }{8y + 4}$ $f^{-1}(x) = \frac{3 + x }{8x + 4}$
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