Answer
$f^{-1}(x) = \sqrt[3] {2 - 5x}$
Work Step by Step
$f(x) = \frac{2 - x^{3}}{5}$
$5y = 2 - x^{3}$
$x^{3} = 2 - 5y$
$x = \sqrt[3] {2 - 5y}$
$f^{-1}(x) = \sqrt[3] {2 - 5x}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises - Page 263: 65
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