## College Algebra 7th Edition

$f^{-1}(x) = \frac{5 + 7x}{x - 2}$
$f(x) = \frac{2x + 5}{x - 7}$ $y = \frac{2x + 5}{x - 7}$ y(x - 7) = 2x + 5 yx - 7y = 2x + 5 yx - 2x = 5 + 7y x(y - 2) = 5 + 7y $x = \frac{5 + 7y}{y - 2}$ $f^{-1}(x) = \frac{5 + 7x}{x - 2}$