College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises: 57

Answer

$f^{-1}(x) = \frac{5 + 7x}{x - 2}$

Work Step by Step

$f(x) = \frac{2x + 5}{x - 7}$ $y = \frac{2x + 5}{x - 7}$ y(x - 7) = 2x + 5 yx - 7y = 2x + 5 yx - 2x = 5 + 7y x(y - 2) = 5 + 7y $x = \frac{5 + 7y}{y - 2}$ $f^{-1}(x) = \frac{5 + 7x}{x - 2}$
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