## College Algebra 7th Edition

$f^{-1}(x) = \frac{2x + 2}{1 - x}$
$f(x) = \frac{x - 2}{x + 2}$ $y = \frac{x - 2}{x + 2}$ y(x + 2) = x - 2 yx + 2y = x - 2 2y + 2 = x - yx 2y + 2 = x( 1 - y) $x = \frac{2y + 2}{1 - y}$ $f^{-1}(x) = \frac{2x + 2}{1 - x}$