College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises: 52

Answer

$f^{-1}(x) = \sqrt[3] {\frac{x - 8}{3}}$

Work Step by Step

$f(x) = 3x^{3} + 8$ $y = 3x^{3} + 8$ $y - 8 = 3x^{3}$ $\frac{y - 8}{3} = x^{3}$ $\sqrt[3] {\frac{y - 8}{3}} = x$ $f^{-1}(x) = \sqrt[3] {\frac{x - 8}{3}}$
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