# Chapter 1, Equations and Graphs - Section 1.5 - Complex Numbers - 1.5 Exercises - Page 131: 81

The statement is true. See below for proof.

#### Work Step by Step

We are given that $z=a+bi$: $z+\overline{z}=(a+bi)+\overline{(a+bi)}=a+bi+a-bi=2a+bi-bi=2a$ Since $a$ is a real number, $2a$ is also a real number.

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