College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.5 - Complex Numbers - 1.5 Exercises - Page 131: 46



Work Step by Step

$\displaystyle \frac{(1+2i)(3-i)}{2+i}=\frac{3-i+6i-2i^{2}}{2+i}=\frac{5+5i}{2+i}*\frac{2-i}{2-i}=\frac{10-5i+10i-5i^{2}}{4-i^{2}}=\frac{10+5i-5*-1}{4--1}=\frac{10+5+5i}{5}=\frac{15+5i}{5} =\frac{15}{5}+\frac{5}{5}i=3+i$
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