Answer
$-4+2i$
Work Step by Step
$\displaystyle \frac{10i}{1-2i}=\frac{10i}{1-2i}*\frac{1+2i}{1+2i}=\frac{10i+20i^{2}}{1-4i^{2}}=\frac{10i+20*-1}{1-4*-1}=\frac{-20+10i}{5}=\frac{5(-4+2i)}{5}=-4+2i$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.5 - Complex Numbers - 1.5 Exercises - Page 131: 41
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