Answer
$2-\frac{4}{3}i$
Work Step by Step
$\displaystyle \frac{4+6i}{3i}=\frac{4+6i}{3i}*\frac{3i}{3i}=\frac{12i+18i^{2}}{9i^{2}}=\frac{12i+18*-1}{9*-1}=\frac{-18+12i}{-9}=\frac{-18}{-9}+\frac{12}{-9}i=2-\frac{4}{3}i$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.5 - Complex Numbers - 1.5 Exercises - Page 131: 43
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
