College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.5 - Complex Numbers - 1.5 Exercises - Page 131: 43



Work Step by Step

$\displaystyle \frac{4+6i}{3i}=\frac{4+6i}{3i}*\frac{3i}{3i}=\frac{12i+18i^{2}}{9i^{2}}=\frac{12i+18*-1}{9*-1}=\frac{-18+12i}{-9}=\frac{-18}{-9}+\frac{12}{-9}i=2-\frac{4}{3}i$
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