Answer
$\frac{8}{5}+\frac{1}{5}i$
Work Step by Step
$\displaystyle \frac{2-3i}{1-2i}=\frac{2-3i}{1-2i}*\frac{1+2i}{1+2i}=\frac{2+4i-3i-6i^{2}}{1-4i^{2}}=\frac{2+1i-6*-1}{1-4*-1}=\frac{2+6+1i}{1+4}=\frac{8+i}{5}=\frac{8}{5}+\frac{1}{5}i$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.5 - Complex Numbers - 1.5 Exercises - Page 131: 39
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