Answer
$-\sqrt{2}-4i\sqrt{6}$
Work Step by Step
$(\sqrt{3}-\sqrt{-4})(\sqrt{6}-\sqrt{-8})= (\sqrt{3}-2i)(\sqrt{6}-2\sqrt{2}i)=\sqrt{18}-2\sqrt{6}i-2\sqrt{6}i+4\sqrt{2}i^2=(\ 3\sqrt{2}-4\sqrt{2})+(-2\sqrt{6}-2\sqrt{6})i=-\sqrt{2}-4i\sqrt{6}$
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