College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.5 - Complex Numbers - 1.5 Exercises - Page 131: 50

Answer

$16=16+0i$

Work Step by Step

$(2i)^{4}=2^{4}i^{4}=16(i^2)^2=16(1)^2=16=16+0i$
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