College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.5 - Complex Numbers - 1.5 Exercises - Page 131: 79


See below.

Work Step by Step

$\overline{z^2}=\overline{(a+bi)^2}=\overline{a^2-b^2+2(ab)i}=a^2-b^2-2(ab)i$ $\overline{z}^2=\overline{(a+bi)}^2=(a-bi)^2=a^2-b^2+-2abi$ Thus they are equal thus we showed what we had to.
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