Answer
$(-\infty,-1]\cup\left[\frac{3}{2},\infty\right)$
Work Step by Step
$2x^2\geq x+3$ (Subtract $x+3$)
$2x^2-x-3\geq 0$ (Factor)
$(x+1)(2x-3)\geq 0$
The solution is $(-\infty,-1]\cup\left[\frac{3}{2},\infty\right)$.
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Chapter 1 Review - Exercises - Page 170: 86
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