Answer
$\left(\frac{10}{3},\infty\right]$
Work Step by Step
$3-x\leq 2x-7$ (Add $x+7$)
$3-x+x+7\leq 2x-7+x-7$
$10\leq 3x$ (Divide by $3$)
$x\geq \frac{10}{3}$
The solution is $\left(\frac{10}{3},\infty\right]$.
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Chapter 1 Review - Exercises - Page 170: 81
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