College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Chapter 1 Review - Exercises: 68

Answer

(a) $\frac{41}{25}-\frac{12}{25}i$ (b) $-20$

Work Step by Step

(a) We multiply the numerator and denominator by the conjugate: $\frac{8+3i}{4+3i}=\frac{8+3i}{4+3i}*\frac{4-3i}{4-3i}=\frac{32-12i-9i^{2}}{16-9i^{2}}=\frac{32-12i-9*-1}{16--9}=\frac{32-12i+9}{16+9}=\frac{41-12i}{25}=\frac{41}{25}-\frac{12}{25}i$ (b) $\sqrt{-10}*\sqrt{-40}=\sqrt{10}i* 2\sqrt{10}i=20i^{2}=-20$
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