College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Chapter 1 Review - Exercises - Page 170: 56


No solution.

Work Step by Step

$x^{2}-3x+9=0$ We solve using the quadratic formula ($a=1, b=-3, c=9$): $ x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}=\frac{--3\pm\sqrt{(-3)^{2}-4*1*9}}{2*1}=\frac{3\pm\sqrt{9-36}}{2}=\frac{3\pm\sqrt{-27}}{2}$ Since we have the square root of a negative, there are no real solutions.
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