Answer
$x=2$ or $x=\pm 2i$
Work Step by Step
We factor and solve:
$x^{3}-2x^{2}+4x-8=0$
$(x-2)(x^{2}+4)$
$x-2=0$ or $x^2+4=0$
$x=2$ or $x=\pm\sqrt{-4}$
$x=2$ or $x=\pm 2i$
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