## College Algebra 7th Edition

$x=2$ or $x=\pm 2i$
We factor and solve: $x^{3}-2x^{2}+4x-8=0$ $(x-2)(x^{2}+4)$ $x-2=0$ or $x^2+4=0$ $x=2$ or $x=\pm\sqrt{-4}$ $x=2$ or $x=\pm 2i$