College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Chapter 1 Review - Exercises - Page 170: 51


$x=\frac{1}{2}$ or $x=-1$

Work Step by Step

We solve by factoring: $2x^{2}+x=1$ $ 2x^{2}+x-1=0$ $(2x-1)(x+1)=0$ $2x-1=0$ or $x+1$=0 $x=\frac{1}{2}$ or $x=-1$
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