Answer
$[-4,-1)$
Work Step by Step
The inequality is not defined at $x=-1$.
$\frac{2x+5}{x+1}\leq 1$ (Multiply by $(x+1)^2$ (positive))
$(2x+5)(x+1)\leq (x+1)^2$
$(2x+5)(x+1)-(x+1)^2\leq 0$
$(x+1)(2x+5-x-1)\leq 0$
$(x+1)(x+4)\leq 0$
The solution is $[-4,-1)$.