College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Chapter 1 Review - Exercises - Page 170: 50


$ x=-12$

Work Step by Step

We solve by factoring: $x^{2}+24x+144=0$ $(x+12)(x+12)=0$ $(x+12)^{2}=0$ $ x+12=0$ $ x=-12$
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