College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Exercise Set 7.2 - Page 686: 63

Answer

$40$ yards

Work Step by Step

We are given the hyperbola; $625y^2-400x^2=250000$ Bring the hyperbola to the standard form: $\dfrac{625y^2}{250000}-\dfrac{400x^2}{250000}=1$ $\dfrac{y^2}{400}-\dfrac{x^2}{625}=1$ Determine $h,k,a,b$: $h=0$ $k=0$ $a^2=400\Rightarrow a=\sqrt{400}=20$ $b^2=625\Rightarrow b=\sqrt{625}=25$ Determine the vertices: $(h,k-a)=(0,0-20)=(0,-20)$ $(h,k+a)=(0,0+20)=(0,20)$ Draw the hyperbola. Determine the shortest distance between the houses: $2a=2\cdot 20=40$ yards
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