Answer
Domain: $(-\infty,-3]\cup[3,\infty)$
Range: $(-\infty,\infty)$
Work Step by Step
We are given the hyperbola:
$\dfrac{x^2}{9}-\dfrac{y^2}{16}=1$
Graph the hyperbola.
From the graph we determine the domain $D$ and the range $R$:
$D=(-\infty,-3]\cup[3,\infty)$
$R=(-\infty,\infty)$
