Answer
Domain: $(-\infty,\infty)$
Range: $(-\infty,-4]\cup[4,\infty)$
Work Step by Step
We are given the hyperbola:
$\dfrac{y^2}{16}-\dfrac{x^2}{9}=1$
Graph the hyperbola.
From the graph we determine the domain $D$ and the range $R$:
$D=(-\infty,\infty)$
$R=(-\infty,-4]\cup[4,\infty)$