Answer
Foci: $(-2-\sqrt{15},3)$ and $(-2+\sqrt{15},3)$.
Work Step by Step
$\displaystyle \frac{(x+2)^{2}}{16}+\frac{(y-3)^{2}}{1}=1$
(major axis horizontal),
$a^{2}=16,$
$a=4$
$b^{2}=1$,
$b=1$
Center: $(-2,3)$
$c^{2}=a^{2}-b^{2}=16-1=15,$
$c=\sqrt{15}\approx 3.873$
Foci are $c$ units right and $c$ units left of center.
Foci: $(-2-\sqrt{15},3)$ and $(-2+\sqrt{15},3)$.
