Answer
Foci:
$(2-\sqrt{5},1)$ and $(2+\sqrt{5},1)$.
Work Step by Step
$9 > 4$ so the major axis is horizontal.
Comparing with
$\displaystyle \frac{(x-h)^{2}}{a^{2}}+ \displaystyle \frac{(y-k)^{2}}{b^{2}}=1$,
$a=3,$
$b=2$
Center: $(h,k)= (2, 1)$
Vertices: $(h-a, k),\quad (h+a, k) $
$(2-3, 1),\quad (2+3, 1)$
$(-1,1),\quad (5,1) $
Foci are $c$ units right and $c$ units left of center,
$c^{2}=a^{2}-b^{2}=9-4=5$
$ c=\sqrt{5}\approx$2.236
Foci:
$(2-\sqrt{5},1)$ and $(2+\sqrt{5},1)$.