Answer
Foci: $(-3-2\sqrt{2},2)$ and $(-3+2\sqrt{2},2)$.
Work Step by Step
$\displaystyle \frac{(x+3)^{2}}{9}+\frac{(y-2)^{2}}{1}=1$
(major axis horizontal),
$a^{2}=9,$
$a=3$
$b^{2}=1$,
$b=1$
Center: $(-3,2)$
$c^{2}=a^{2}-b^{2}=9-1=8$
$c=\sqrt{8}=2\sqrt{2}\approx 2.828$
Foci are $c$ units right and $c$ units left of center.
Foci: $(-3-2\sqrt{2},2)$ and $(-3+2\sqrt{2},2)$.
