Answer
Foci: $(-3-2\sqrt{3},2)$ and $(-3+2\sqrt{3},2)$.
Work Step by Step
Bring to stadard form (divide with 16)
$\displaystyle \frac{(x+3)^{2}}{16}+\frac{(y-2)^{2}}{4}=1$
$a^{2}=16,$ (main axis horizontal), $a=4$
$b^{2}=4$, $b=2$
Center: $(h,k)=(-3,2)$
$c^{2}=a^{2}-b^{2}=16-4=12$
$ c=\sqrt{12}=2\sqrt{3}\approx$3.464
Foci are $c$ units right and $c$ units left of center.
Foci: $(-3-2\sqrt{3},2)$ and $(-3+2\sqrt{3},2)$.
