College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Exercise Set 7.1 - Page 671: 31


$\displaystyle \frac{x^{2}}{16}+\frac{y^{2}}{4}=1$

Work Step by Step

Major axis horizontal: $\displaystyle \frac{(x-h)^{2}}{a^{2}}+ \displaystyle \frac{(y-k)^{2}}{b^{2}}=1$ Major and minor axes have lengths $2a$ and $2b$ $2a=8 \Rightarrow a=4$ $2b=4\Rightarrow b=2$ Center: $(h,k)=(0,0)$ $\displaystyle \frac{x^{2}}{4^{2}}+\frac{y^{2}}{2^{2}}=1$ $\displaystyle \frac{x^{2}}{16}+\frac{y^{2}}{4}=1$
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