College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Exercise Set 7.1 - Page 671: 29

Answer

$\displaystyle \frac{x^{2}}{13}+\frac{y^{2}}{9}=1$

Work Step by Step

With the given information, the foci are $c=2$ units left/right of the point (0,0) so, the major axis is horizontal, so, the standard form the equation is $\displaystyle \frac{(x-h)^{2}}{a^{2}}+ \displaystyle \frac{(y-k)^{2}}{b^{2}}=1$. The y-intercepts give: $b=3$. $(h,k)=(0,0)$ $b=3$ $c=2$ From $c^{2}=a^{2}-b^{2}$ $a^{2}=b^{2}+c^{2}=9+4=13$ so the equation is $\displaystyle \frac{x^{2}}{13}+\frac{y^{2}}{9}=1$
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