## College Algebra (6th Edition)

Foci: $(0,2+\sqrt{11})$ and $(0,2-\sqrt{11})$.
$\displaystyle \frac{(x-0)^{2}}{25}+\frac{(y-2)^{2}}{36}=1$ (major axis vertical), $a^{2}=36,$ $a=6$ $b^{2}=25$, $b=5$ Center: $(h,k)=(0, 2)$ $c^{2}=a^{2}-b^{2}=36-25=11$ $c=\sqrt{11}\approx 3.317$ Foci are $c$ units above and $c$ units below the center. Foci: $(0,2+\sqrt{11})$ and $(0,2-\sqrt{11})$.