College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Exercise Set 7.1 - Page 671: 32

Answer

$\displaystyle \frac{x^{2}}{36}+\frac{y^{2}}{9}=1$

Work Step by Step

Major axis horizontal: $\displaystyle \frac{(x-h)^{2}}{a^{2}}+ \displaystyle \frac{(y-k)^{2}}{b^{2}}=1$ Major and minor axes have lengths $2a$ and $2b$ $2a=12 \Rightarrow a=6$ $2b=6\Rightarrow b=3$ Center: $(h,k)=(0,0)$ $\displaystyle \frac{x^{2}}{6^{2}}+\frac{y^{2}}{3^{2}}=1$ $\displaystyle \frac{x^{2}}{36}+\frac{y^{2}}{9}=1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.