## College Algebra (6th Edition)

$\{-2(1-i),-2(1+i)\}$
$(x+2)^{2}+4=0$ $(x+2)^{2}=-4$ $(x+2)=\sqrt -4$ Using $\sqrt -b = i\sqrt b$ $(x+2)=i\sqrt 4$ $(x+2)=±2i$ $x=-2±2i$ $x=-2+2i$ or $x=-2-2i$ $x=-2(1-i)$ or $x=-2(1+i)$