College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Summary, Review, and Test - Review Exercises - Page 204: 80



Work Step by Step

$(x+2)^{2}+4=0$ $(x+2)^{2}=-4$ $(x+2)=\sqrt -4$ Using $\sqrt -b = i\sqrt b$ $(x+2)=i\sqrt 4$ $(x+2)=±2i$ $x=-2±2i$ $x=-2+2i$ or $x=-2-2i$ $x=-2(1-i)$ or $x=-2(1+i)$
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