#### Answer

$\{-2(1-i),-2(1+i)\}$

#### Work Step by Step

$(x+2)^{2}+4=0$
$(x+2)^{2}=-4$
$(x+2)=\sqrt -4$
Using $\sqrt -b = i\sqrt b$
$(x+2)=i\sqrt 4$
$(x+2)=±2i$
$x=-2±2i$
$x=-2+2i$ or $x=-2-2i$
$x=-2(1-i)$ or $x=-2(1+i)$

Published by
Pearson

ISBN 10:
0-32178-228-3

ISBN 13:
978-0-32178-228-1

$\{-2(1-i),-2(1+i)\}$

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