College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Summary, Review, and Test - Review Exercises - Page 204: 49



Work Step by Step

Simply multiply the terms outside and inside the parentheses. Then turn $i^{2}$ into $-1$ since they are equal. $4i(3i-2)$ $12i^{2}-8i$ $-12-8i$
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