Answer
a. $14100+1500x=41700+800x$
b. year $2022$, enrollment $32100$
Work Step by Step
a. For college-A, we have $y_1=14100+1500x$ and for college-B, we have $y_2=41700+800x$. For the two colleges to have the same enrollment, we have $y_1=y_2$ which leads to $14100+1500x=41700+800x$
b. Based on the table given in the Exercise, when $x=12$, $Y_1=Y_2=32100$, this happens in year $2010+x=2022$ with an equal enrollment of $32100$
