College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Summary, Review, and Test - Review Exercises - Page 204: 61



Work Step by Step

$\frac{x^{2}}{2}+5=-3$ $\frac{x^{2}}{2}=-3-5$ $\frac{x^{2}}{2}=-8$ $x^{2}=-16$ $x=±\sqrt -16$ Using $\sqrt -b = i\sqrt b$ $x=±i\sqrt 16$ $x=±4i$
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