Answer
$x=±4i$
Work Step by Step
$\frac{x^{2}}{2}+5=-3$
$\frac{x^{2}}{2}=-3-5$
$\frac{x^{2}}{2}=-8$
$x^{2}=-16$
$x=±\sqrt -16$
Using $\sqrt -b = i\sqrt b$
$x=±i\sqrt 16$
$x=±4i$
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