College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Summary, Review, and Test - Review Exercises - Page 204: 73

Answer

$\{5,\frac{1}{2}\}$

Work Step by Step

$2x^{2}-11x+5=0$ Using quadratic formula, $x= \frac{-b±\sqrt (b^{2}-4ac)}{2a}$ Substituting $a=2, b=-11, c=5$ $x= \frac{11±\sqrt ((-11)^{2}-4(2)(5))}{2(2)}$ $x= \frac{11±\sqrt (121-40)}{4}$ $x= \frac{11±\sqrt81}{4}$ $x= \frac{11±9}{4}$ $x= \frac{11+9}{4}$ or $x= \frac{11-9}{4}$ $x= \frac{20}{4}$ or $x= \frac{2}{4}$ $x= 5$ or $x= \frac{1}{2}$
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