Answer
$x=\frac{4+3\sqrt 2}{3}$ or $x=\frac{4-3\sqrt 2}{3}$
Work Step by Step
$(3x-4)^{2}=18$
$(3x-4)= ±\sqrt 18$
$(3x-4)= ±\sqrt (9 \times 2)$
$(3x-4)= ±3 \sqrt 2$
$3x= 4 ±3 \sqrt 2$
$x=\frac{4 ±3 \sqrt 2}{3}$
$x=\frac{4+3\sqrt 2}{3}$ or $x=\frac{4-3\sqrt 2}{3}$
