College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Summary, Review, and Test - Review Exercises - Page 204: 65

Answer

The constant added should be $\frac{9}{4}$ The trinomial factored is (x-$\frac{3}{2}$)$^2$

Work Step by Step

C=($\frac{b}{2}$)$^2$ C=($\frac{-3}{2}$)$^2$ C=$\frac{9}{4}$ x$^2$-3x+$\frac{9}{4}$ (x-$\frac{3}{2}$)(x-$\frac{3}{2}$) (x-$\frac{3}{2}$)$^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.