Answer
$\{-2,\frac{10}{3}\}$
Work Step by Step
$(3x+5)(x-3)=5$
$3x^{2}+5x-9x-15-5=0$
$3x^{2}-4x-20=0$
By factoring,
$3x^{2}+6x-10x-20=0$
$3x(x+2)-10(x+2)=0$
$(3x-10)(x+2)=0$
$3x-10=0$ or $x+2=0$
$3x=10$ or $x=-2$
$x=\frac{10}{3}$ or $x=-2$
