College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Summary, Review, and Test - Review Exercises - Page 204: 64

Answer

Constant should be added to the binomial: $100$ Trinomial: $x^{2}+20x+100$ Factors: $(x+10)(x+10)$

Work Step by Step

$x^{2}+20x$ By adding the square of half the co-efficient of $x$, we get $x^{2}+20x+100$ By factoring, $x^{2}+20x +100=(x+10)^{2}$ $(x+10)(x+10)$
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