## College Algebra (6th Edition)

Constant should be added to the binomial: $100$ Trinomial: $x^{2}+20x+100$ Factors: $(x+10)(x+10)$
$x^{2}+20x$ By adding the square of half the co-efficient of $x$, we get $x^{2}+20x+100$ By factoring, $x^{2}+20x +100=(x+10)^{2}$ $(x+10)(x+10)$