Answer
$i\sqrt 2$
Work Step by Step
$\sqrt -32 - \sqrt -18$
Using $\sqrt -b = i\sqrt b$
$\sqrt -32 - \sqrt -18 = i\sqrt 32 - i\sqrt18$
$=i\sqrt (16 \times 2) - i\sqrt (9 \times 2)$
$=4i\sqrt 2 -3 i\sqrt2$
$=i\sqrt 2$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 1 - Summary, Review, and Test - Review Exercises - Page 204: 55
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
