Answer
$i\sqrt 2$
Work Step by Step
$\sqrt -32 - \sqrt -18$
Using $\sqrt -b = i\sqrt b$
$\sqrt -32 - \sqrt -18 = i\sqrt 32 - i\sqrt18$
$=i\sqrt (16 \times 2) - i\sqrt (9 \times 2)$
$=4i\sqrt 2 -3 i\sqrt2$
$=i\sqrt 2$
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