College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2 - Page 119: 96



Work Step by Step

Use the order of operations (PEMDAS) to solve this problem. $-2[7-[4-2(1-x)+3]]=10-[4x-2(x-3)]$ $-2[7-[4-2+x+3]]=10-[4x-2x+6]$ $-2[7-x+5]=10-2x+6$ $-2[12-x]=16-2x$ $-24+2x=16-2x$ $4x=40$ $x=10$
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