#### Answer

$x=10$

#### Work Step by Step

Use the order of operations (PEMDAS) to solve this problem.
$-2[7-[4-2(1-x)+3]]=10-[4x-2(x-3)]$
$-2[7-[4-2+x+3]]=10-[4x-2x+6]$
$-2[7-x+5]=10-2x+6$
$-2[12-x]=16-2x$
$-24+2x=16-2x$
$4x=40$
$x=10$

Published by
Pearson

ISBN 10:
0-32178-228-3

ISBN 13:
978-0-32178-228-1

$x=10$

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