## College Algebra (6th Edition)

$x=10$
Use the order of operations (PEMDAS) to solve this problem. $-2[7-[4-2(1-x)+3]]=10-[4x-2(x-3)]$ $-2[7-[4-2+x+3]]=10-[4x-2x+6]$ $-2[7-x+5]=10-2x+6$ $-2[12-x]=16-2x$ $-24+2x=16-2x$ $4x=40$ $x=10$