Answer
$x=10$
Work Step by Step
Use the order of operations (PEMDAS) to solve this problem.
$-2[7-[4-2(1-x)+3]]=10-[4x-2(x-3)]$
$-2[7-[4-2+x+3]]=10-[4x-2x+6]$
$-2[7-x+5]=10-2x+6$
$-2[12-x]=16-2x$
$-24+2x=16-2x$
$4x=40$
$x=10$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 1 - Equations and Inequalities - Exercise Set 1.2 - Page 119: 96
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