## College Algebra (6th Edition)

$\frac{4x}{x+3}$-$\frac{12}{x-3}$=$\frac{4x^2+36}{x^2-9}$ (x cannot equal 3 or -3) 4x$^2$-12x-12x-36=4x$^2$+36 -24x=72 x$\ne$-3 There is no solution so this is an inconsistent equation