## College Algebra (6th Edition)

$2$
Using the second equation first Solve for x $4(x — 2) + 2 = 4x — 2(2 — x)$ $4x — 8 + 2 = 4x — 4 +2x$ $4x — 6 = 6x — 4$ $-2 = 2x$ $x = -1$ Now plug in $x=-1$ into the first equation $x^{2}-x$ $(-1)^{2} -(-1)$ $1+1$ $2$