College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2 - Page 119: 60



Work Step by Step

If you have trouble following the steps below, please review the order of operations (PEMDAS) or the distributive property. Note that, because we are told that $y=0$, the expression involving $x$ is also equal to zero. $y=\frac{1}{5x+5}-\frac{3}{x+1}+\frac{7}{5}=0$ $\frac{1}{5(x+1)}-\frac{3}{x+1}=-\frac{7}{5}$ $\frac{1}{5(x+1)}-\frac{15}{5(x+1)}=-\frac{7}{5}$ $\frac{1-15}{5(x+1)}=-\frac{7}{5}$ $\frac{-14}{5(x+1)}=-\frac{7}{5}$ $-14=-\frac{7}{5}[5(x+1)]$ $-14=-7(x+1)$ $-14=-7x-7$ $-7x=-14+7$ $-7x=-7$ $x=1$
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