## College Algebra (6th Edition)

$x=3$
Because we are told that $y_{1}=y_{2}$, we may set the two equations equal to one another and solve: $7(3x-2)+5=6(2x-1)+24$ $21x-14+5=12x-6+24$ $21x-9=12x+18$ $21x-12x=18+9$ $9x=27$ $x=3$ The two equations describe a pair of intersecting lines, so there is only one solution.