College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2 - Page 119: 70

Answer

$x=46/5$

Work Step by Step

$\frac{x+2}{7}=5-\frac{x+1}{3}$ $\frac{1}{7}x+\frac{2}{7}=5-\frac{1}{3}x-\frac{1}{3}$ $\frac{1}{7}x+\frac{1}{3}x=5-\frac{1}{3}-\frac{2}{7}$ $\frac{10}{21}x=\frac{92}{21}$ $10x=92$ $x=\frac{92}{10}=\frac{46}{5}$
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