## College Algebra (6th Edition)

$x=3$ conditional equation
$\frac{3}{x-3}=\frac{x}{x-3}+3$ $\frac{3}{x-3}=\frac{x}{x-3}+3(\frac{x-3}{x-3})$ $\frac{3}{x-3}=\frac{x+3(x-3)}{x-3}$ $3=x+3(x-3)$ $3=x+3x-9$ $3=4x-9$ $4x=12$ $x=3$